Answer. (i) In 1956, an Act was passed which recognised Sinhala as the only official language, thus disregarding Tamil language. ... (iv) Sri Lankan Tamil felt that none of the major political parties led by Buddhist Sinhala leaders were sensitive to their language and culture.
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The mechanism of vision:i. The light rays in visible wavelength is focussed on the retina through the cornea and lens generate potentials (impulses) in rods and cones. ii. The photopigments which is composed of opsin and retinal is dissociated into opsin and retinal because of light. . iii. The change in the structure of the opsin causes changes in the membrane permeability. iv. A potential differences is generated in the photoreceptor cells which produces signal that generating action potentials in the ganglion cells through the bipolar cells. v. The action potential is transmitted by the o
Volume of the air bubble, V1 = 1.0 cm3 = 1.0 × 10–6 m3 Bubble rises to height, d = 40 m Temperature at a depth of 40 m, T1 = 12°C = 285 K Temperature at the surface of the lake, T2 = 35°C = 308 K The pressure on the surface of the lake, P2 = 1 atm = 1 ×1.013 × 105 PaThe pressure at the depth of 40 m, P1 = 1 atm + dρg where, ρ is the density of water = 103 kg/m3 g is the acceleration due to gravity = 9.8 m/s2 Therefore, P1 = 1.013 × 105 + 40 × 103 × 9.8 = 493300 Pa We have, P1V1 / T1 = P2V2 / T2 where, V2 is the volume of the air bubble when it reaches the surface. V2 = P1V1T2 / T1P2
J.B. Priestley has titled his one-act play ‘Mother’s Day’. The title conveys a message. Husbands and children must respect wives and mothers in their families. They must not order and keep them running all the time doing one work or the other. Mrs Pearson with Mrs Fitzgerald’s help succeeds in setting her spoilt children and husband right. The mother carries the day and wins over all the members of the family to her side.
Let BC be the height of the tower and CD be the pole of height 5m fixed on the top of the tower. Let BC = h m.
The angle of elevation of top of the pole from point A on the ground be 60° and the angle of depression of the point A from the top of the tower be 45°, i.e. ∠ BAD = 60° and ∠ BAC = 45°.In right triangle ABC, we have
In right triangle ABD, we have
Comparing (i) and (ii), we get
Hence, height of the tower be 6.83 m.
The angle of elevation of top of the pole from point A on the ground be 60° and the angle of depression of the point A from the top of the tower be 45°, i.e. ∠ BAD = 60° and ∠ BAC = 45°.In right triangle ABC, we have
In right triangle ABD, we have
Comparing (i) and (ii), we get
Hence, height of the tower be 6.83 m.
Mass of Organic compound =0.157 gMass of barium sulphate = 0.4813 gMolecular mass of BaSO4 = 137 + 32 + 64 = 233 g mol-1233 g BaSO4 contains 32 g sulphur
Given, length of the elctric dipole = 4cm=4×10-2 mangle made with the elctric field-θ=60∘Torque experienced by the dipole-τ = 43 Nmcharge on the dipole-q=±8nC = ±8×10-9 Ci) magnitude of Electric field-E τ= pE sinθ = q × 2a × E sinθ ⇒ 43 = 8×10-9 × 4×10-2 × E × sin 60° ⇒ E = 43×232 ×10-11×3 = 14×1011 = 2.5 × 1010 NC-1(ii) magnitude of potential energy of the dipole U = -pE cos θ = -q×2a×E cos θ =-8×10-9×2×10-2×2.5×1010 cos 60°= - 2J.
When M. Hamel gave his last French lesson in the classroom, there was no commotion. There was pin-drop silence. He was politely and dedicatedly talking with the students. There was no strictness, looked solemn, serious and deeply grieved. Whenever he spoke, his throat choked. He felt as if his bodily parts were being pierced.
The formula of dichlorotetraqua chromium (Ill) chloride is
On ionisation it generates only one CI- ion.
Initial 10010.01
after ionisation
1 mol
1 mol
One mole of CI- ions reacts with only 1 mole of AgN03 molecules to produce 1 mole of AgCl.
therefore, 1 mmol orl x 10-3 mole reacts with AgN03 to give AgCI.
On ionisation it generates only one CI- ion.
Initial 10010.01
after ionisation
1 mol
1 mol
One mole of CI- ions reacts with only 1 mole of AgN03 molecules to produce 1 mole of AgCl.
therefore, 1 mmol orl x 10-3 mole reacts with AgN03 to give AgCI.
The place is clearly the magnetic pole of earth as needle rotates in vertical plane and, not in horizontal plane we
have,
Hence,
(a) Horizontal component of earth's magnetic field at the magnetic poles, BH =
(b) Angle of dip at the magnetic poles of earth, 6 = goo.
o.
have,
Hence,
(a) Horizontal component of earth's magnetic field at the magnetic poles, BH =
(b) Angle of dip at the magnetic poles of earth, 6 = goo.
o.
Answer :- CgHsC(CH3)(CgHs)Br............Sy reaction involves the formation of carbocation intermediate. More the stability of carbocation more is the reactivity of alkyl/aryl halides towards Sy reaction.
The intermediate carbocations formed by given halides as:
2) CoHsCH(CGH)Br — (Cas)aCH + Br™
) CgHsCH(CHZ)Br = CgHSC*H(CH3) + B~
€) CgHsC(CH3)(CgHs)Br = (CoHsC*(CHy) + Br™
@) CaHsCHyBr CgHsCH, + Br
The order of stability of these carbocations is as
(CeHsC*(CH3) > (CgHs),CTH > CoHsCPHICHS) > CoHsC*Hy
Thus, CgHsC(CHs)(CeHs)Br is most reactive towards Sy1 reaction.
Sy1 reaction involve
The intermediate carbocations formed by given halides as:
2) CoHsCH(CGH)Br — (Cas)aCH + Br™
) CgHsCH(CHZ)Br = CgHSC*H(CH3) + B~
€) CgHsC(CH3)(CgHs)Br = (CoHsC*(CHy) + Br™
@) CaHsCHyBr CgHsCH, + Br
The order of stability of these carbocations is as
(CeHsC*(CH3) > (CgHs),CTH > CoHsCPHICHS) > CoHsC*Hy
Thus, CgHsC(CHs)(CeHs)Br is most reactive towards Sy1 reaction.
Sy1 reaction involve
बंद द्वार की साँकल खोलने के लिए ललदय ने उपाय सुझाया है कि भोग-विलास और त्याग के बीच संतुलन बनाए रखना, मनुष्य को सांसारिक विषयों में न तो अधिक लिप्त और न ही उससे विरक्त होना चाहिए बल्कि उसे बीच का मार्ग अपनाना चाहिए। जिस दिन मनुष्य के हृदय में ईश्वर भक्ति जागृत हो गई अज्ञानता के सारे अंधकार स्वयं ही समाप्त हो जाएँगे। इसलिए सच्चे मन से प्रभु की साधना करो, अपने अन्त:करण व बाह्य इन्द्रियों पर विजय प्राप्त कर हृदय में प्रभु का जाप करो, सुख व दुख को समान भाव से भोगों। यही उपाय कवियत्री ने सुझाए हैं।
(i) [Ni(CN)4]2–: In case the valence shell electronic configuration of ground state Ni atom is 3d8 4s2. There is Ni2+ ion for which the electronic configuration in the valence shell is 3d8 4s0. In presence of strong field CN- ions, all the electrons are paired up. The empty 4d, 3s and two 4p orbitals undergo dsp2 hybridization to make bonds with CN- ligands in square planar geometry(ii) Ni(CO)4 : In case the valence shell electronic configuration of ground state Ni atom is 3d8 4s2. All of these 10 electrons are pushed into 3d orbitals and get paired up when strong field CO ligands approach
The narrator was tempted to keep Tricki as a permanent guest because Mrs Pumphrey had started bringing around two dozen eggs at a time to build Tricki’s strength. Later, she started sending bottles of wine to help enriching Tricki s blood. The narrator and his partners started enjoying the eggs, wine and brandy meant for Tricki as it was too much for Tricki. The doctor enjoyed the days of deep contentment relishing the eggs, wine and brandy.
In the past, the shehnai was a part of the naubat or traditional ensemble of nine instruments found at royal courts. It was used only in temples and weddings till recently. Ustad Bismillah Khan gets the credit for bringing this instrument onto the classical stage.
Olfactory indicators are those indicators that help to identify whether the given solution is acidic or basic by changing their smell instead of colour as other indicators do. For example onion, vanilla, clove, etcOnion: Paste or juice of onion loses its smell when added with base. It does not change its smell with acid.Vanilla: The smell of vanilla vanishes with base, but it’s smell does not vanishes with an acid.
No, Lencho did not try to find out who had sent the money to him. On account of his faith in God, he was very confident that God would definitely help him. He was eagerly waiting for God s response to his letter.
Venturimeter is based on Bernoulli s theorem. It consists of a two truncated tubes connected by a pipe at narrow ends. The pipe connecting the two tubes is called throat as shown in figure.
The venturimeter tube is positioned horizontally and the liquid is made to enter in it at end A and after passing through throat BC, it leaves tube at end D. Let at A, the area of cross-section of tube be a1, pressure of liquid be P1 and velocity be v1 And at the throat, the area of cross-section of tube be a2 pressure of liquid be P2 and velocity be v2
The venturimeter tube is positioned horizontally and the liquid is made to enter in it at end A and after passing through throat BC, it leaves tube at end D. Let at A, the area of cross-section of tube be a1, pressure of liquid be P1 and velocity be v1 And at the throat, the area of cross-section of tube be a2 pressure of liquid be P2 and velocity be v2
Here, we haver = 28 cm and Now, Area of Minor sector In right triangle OMA, we have Area of one design = 77.47 cm2 Area of six design = 77.47 x 6 = 464.82 cm2 = 464.82 x 0.35 = Rs. 162.68
To convert from Propene to Propan-2-ol, the addition of H2SO4 takes place in accordance with Markovnikov ‘s rule i.e.